From 7d06d6e18651cb183a3723fa21ef62935ea08647 Mon Sep 17 00:00:00 2001 From: Daniel Thau Date: Thu, 2 Sep 2021 07:41:08 -0400 Subject: [PATCH] awk: fix printf %% A refactor of the awk printf code in e2e3802987266c98df0efdf40ad5da4b07df0113 appears to have broken the printf interpretation of two percent signs, which normally outputs only one percent sign. The patch below brings busybox awk printf behavior back into alignment with the pre-e2e380 behavior, the busybox printf util, and other common (awk and non-awk) printf implementations. function old new delta awk_printf 626 672 +46 Signed-off-by: Daniel Thau Signed-off-by: Denys Vlasenko --- editors/awk.c | 9 ++++++++- testsuite/awk.tests | 6 ++++++ testsuite/printf.tests | 5 +++++ 3 files changed, 19 insertions(+), 1 deletion(-) diff --git a/editors/awk.c b/editors/awk.c index 3adbca7aa..f7b8ef0d3 100644 --- a/editors/awk.c +++ b/editors/awk.c @@ -2346,8 +2346,15 @@ static char *awk_printf(node *n, size_t *len) size_t slen; s = f; - while (*f && (*f != '%' || *++f == '%')) + while (*f && *f != '%') f++; + c = *++f; + if (c == '%') { /* double % */ + slen = f - s; + s = xstrndup(s, slen); + f++; + goto tail; + } while (*f && !isalpha(*f)) { if (*f == '*') syntax_error("%*x formats are not supported"); diff --git a/testsuite/awk.tests b/testsuite/awk.tests index dc2ae2e11..bcaafe8fd 100755 --- a/testsuite/awk.tests +++ b/testsuite/awk.tests @@ -463,4 +463,10 @@ testing "awk \"cmd\" | getline" \ "HELLO\n" \ '' '' +# printf %% should print one % (had a bug where it didn't) +testing 'awk printf %% prints one %' \ + "awk 'BEGIN { printf \"%%\n\" }'" \ + "%\n" \ + '' '' + exit $FAILCOUNT diff --git a/testsuite/printf.tests b/testsuite/printf.tests index 34a65926e..050edef71 100755 --- a/testsuite/printf.tests +++ b/testsuite/printf.tests @@ -79,6 +79,11 @@ testing "printf understands %Ld" \ "-5\n""0\n" \ "" "" +testing "printf understands %%" \ + "${bb}printf '%%\n' 2>&1; echo \$?" \ + "%\n""0\n" \ + "" "" + testing "printf handles positive numbers for %d" \ "${bb}printf '%d\n' 3 +3 ' 3' ' +3' 2>&1; echo \$?" \ "3\n"\