gramps/gramps/py-compile
Don Allingham 391abdc688 Initial revision
svn: r3
2001-05-13 01:56:57 +00:00

69 lines
1.4 KiB
Bash

#!/bin/sh
# called as "py-compile [--basedir DIR] PY_FILES ...
if [ -z "$PYTHON" ]; then
PYTHON=python
fi
basedir=
case "$1" in
--basedir)
basedir=$2
shift 2
;;
--help)
echo "Usage: py-compile [--basedir DIR] PY_FILES ..."
echo "Byte compile some python scripts. This should be performed"
echo "after they have been moved to the final installation location"
exit 0
;;
--version)
echo "py-compile version 0.0"
exit 0
;;
esac
if [ $# = 0 ]; then
echo "No files given to $0" 1>&2
exit 1
fi
# if basedir was given, then it should be prepended to filenames before
# byte compilation.
if [ -z "$basedir" ]; then
trans="path = file"
else
trans="path = os.path.join('$basedir', file)"
fi
$PYTHON -c "
import sys, os, string, py_compile
files = '''$*'''
print 'Byte-compiling python modules...'
for file in string.split(files):
$trans
if not os.path.exists(path) or not (len(path) >= 3 and path[-3:] == '.py'):
continue
print file,
sys.stdout.flush()
py_compile.compile(path)
print" || exit $?
# this will fail for python < 1.5, but that doesn't matter ...
$PYTHON -O -c "
import sys, os, string, py_compile
files = '''$*'''
print 'Byte-compiling python modules (optimised versions) ...'
for file in string.split(files):
$trans
if not os.path.exists(path) or not (len(path) >= 3 and path[-3:] == '.py'):
continue
print file,
sys.stdout.flush()
py_compile.compile(path)
print" 2>/dev/null || :