Make bitfield assignment operator public
This change needs to be made to get the code compiling again. It was suggested after a conversation with Lioncash. The conversation can be seen here: https://user-images.githubusercontent.com/20753089/45064197-b6107800-b0b2-11e8-9db8-f696299fb86a.PNG
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@ -111,12 +111,6 @@
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template <std::size_t Position, std::size_t Bits, typename T>
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template <std::size_t Position, std::size_t Bits, typename T>
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struct BitField {
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struct BitField {
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private:
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private:
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// We hide the copy assigment operator here, because the default copy
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// assignment would copy the full storage value, rather than just the bits
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// relevant to this particular bit field.
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// We don't delete it because we want BitField to be trivially copyable.
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BitField& operator=(const BitField&) = default;
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// StorageType is T for non-enum types and the underlying type of T if
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// StorageType is T for non-enum types and the underlying type of T if
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// T is an enumeration. Note that T is wrapped within an enable_if in the
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// T is an enumeration. Note that T is wrapped within an enable_if in the
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// former case to workaround compile errors which arise when using
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// former case to workaround compile errors which arise when using
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@ -128,6 +122,8 @@ private:
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using StorageTypeU = std::make_unsigned_t<StorageType>;
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using StorageTypeU = std::make_unsigned_t<StorageType>;
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public:
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public:
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BitField& operator=(const BitField&) = default;
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/// Constants to allow limited introspection of fields if needed
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/// Constants to allow limited introspection of fields if needed
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static constexpr size_t position = Position;
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static constexpr size_t position = Position;
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static constexpr size_t bits = Bits;
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static constexpr size_t bits = Bits;
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