c71c18957d
Hello,
when calling seq with
seq 1 1
it generates an "endless" list of numbers until the counter wraps and
reaches 1 again. The follwoing small patch should introduce the
expected behavior (output of 1 and termination):
regards,
Jean
45 lines
1.2 KiB
C
45 lines
1.2 KiB
C
/*
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* This program is free software; you can redistribute it and/or modify
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* it under the terms of version 2 of the GNU General Public License as
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* published by the Free Software Foundation.
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*
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* This program is distributed in the hope that it will be useful,
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* but WITHOUT ANY WARRANTY; without even the implied warranty of
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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* GNU Library General Public License for more details.
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*
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* You should have received a copy of the GNU General Public License
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* along with this program; if not, write to the Free Software
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* Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
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*/
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#include <stdio.h>
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#include <stdlib.h>
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#include "busybox.h"
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extern int seq_main(int argc, char **argv)
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{
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double last;
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double first = 1;
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double increment = 1;
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double i;
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if (argc == 4) {
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first = atof(argv[1]);
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increment = atof(argv[2]);
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}
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else if (argc == 3) {
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first = atof(argv[1]);
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}
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else if (argc != 2) {
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bb_show_usage();
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}
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last = atof(argv[argc - 1]);
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for (i = first; ((first <= last) ? (i <= last): (i >= last));i += increment) {
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printf("%g\n", i);
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}
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return(EXIT_SUCCESS);
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}
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