66 lines
		
	
	
		
			1.0 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			66 lines
		
	
	
		
			1.0 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
| /* vi: set sw=4 ts=4: */
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| /*
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|  * parse_num.c		- Parse the number of blocks
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|  *
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|  * Copyright (C) 2004,2005  Theodore Ts'o <tytso@mit.edu>
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|  *
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|  * This file can be redistributed under the terms of the GNU Library General
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|  * Public License
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|  */
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| 
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| #include "e2p.h"
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| 
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| #include <stdlib.h>
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| 
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| unsigned long parse_num_blocks(const char *arg, int log_block_size)
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| {
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| 	char *p;
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| 	unsigned long long num;
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| 
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| 	num = strtoull(arg, &p, 0);
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| 
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| 	if (p[0] && p[1])
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| 		return 0;
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| 
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| 	switch (*p) {		/* Using fall-through logic */
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| 	case 'T': case 't':
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| 		num <<= 10;
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| 	case 'G': case 'g':
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| 		num <<= 10;
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| 	case 'M': case 'm':
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| 		num <<= 10;
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| 	case 'K': case 'k':
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| 		num >>= log_block_size;
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| 		break;
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| 	case 's':
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| 		num >>= 1;
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| 		break;
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| 	case '\0':
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| 		break;
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| 	default:
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| 		return 0;
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| 	}
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| 	return num;
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| }
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| 
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| #ifdef DEBUG
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| #include <unistd.h>
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| #include <stdio.h>
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| 
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| main(int argc, char **argv)
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| {
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| 	unsigned long num;
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| 	int log_block_size = 0;
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| 
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| 	if (argc != 2) {
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| 		fprintf(stderr, "Usage: %s arg\n", argv[0]);
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| 		exit(1);
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| 	}
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| 
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| 	num = parse_num_blocks(argv[1], log_block_size);
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| 
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| 	printf("Parsed number: %lu\n", num);
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| 	exit(0);
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| }
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| #endif
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