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display whether an option takes an argument in the usage output

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This commit is contained in:
Mike Frysinger 2007-09-25 22:57:32 +00:00
parent 8ce7911f10
commit 7d9acd968f
1 changed files with 8 additions and 3 deletions
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11
src/_usage.c
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@ -9,15 +9,20 @@
static void usage (int exit_status) static void usage (int exit_status)
{ {
const char * const has_arg[] = { "", "<arg>", "[arg]" };
int i; int i;
printf ("Usage: " APPLET " [options] "); printf ("Usage: " APPLET " [options] ");
#ifdef extraopts #ifdef extraopts
printf (extraopts); printf (extraopts);
#endif #endif
printf ("\n\nOptions: [" getoptstring "]\n"); printf ("\n\nOptions: [" getoptstring "]\n");
for (i = 0; longopts[i].name; ++i) for (i = 0; longopts[i].name; ++i) {
printf (" -%c, --%-15s %s\n", longopts[i].val, longopts[i].name, int len = printf (" -%c, --%s %s", longopts[i].val, longopts[i].name,
longopts_help[i]); has_arg[longopts[i].has_arg]);
while (++len < 25)
printf (" ");
puts (longopts_help[i]);
}
exit (exit_status); exit (exit_status);
} }