sub[ug]id: compare range before comparing username/UID, to avoid unnecessary syscalls
Change suggested by Nicolas François as performance optimization. Performance penalty would be really noticeable when usernames are stored in remote databases (ldap). Signed-off-by: Serge Hallyn <serge.hallyn@ubuntu.com>
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@ -245,36 +245,38 @@ static const struct subordinate_range *find_range(struct commonio_db *db,
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unsigned long first = range->start;
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unsigned long last = first + range->count - 1;
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/*
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* First check if range owner is specified as numeric UID
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* and if it matches.
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*/
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if (0 != strcmp(range->owner, owner_uid_string)) {
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/*
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* Ok, this range owner is not specified as numeric UID
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* we are looking for. It may be specified as another
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* UID or as a literal username.
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*
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* If specified as another UID, the call to getpwnam()
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* will return NULL.
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*
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* If specified as literal username, we will get its
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* UID and compare that to UID we are looking for.
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*/
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const struct passwd *range_owner_pwd;
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range_owner_pwd = getpwnam(range->owner);
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if (NULL == range_owner_pwd) {
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continue;
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}
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if (owner_uid != range_owner_pwd->pw_uid) {
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continue;
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}
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/* For performance reasons check range before using getpwnam() */
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if ((val < first) || (val > last)) {
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continue;
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}
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/* Owner matches, now let us check this UID/GID range */
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if ((val >= first) && (val <= last)) {
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/*
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* Range matches. Check if range owner is specified
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* as numeric UID and if it matches.
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*/
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if (0 == strcmp(range->owner, owner_uid_string)) {
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return range;
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}
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/*
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* Ok, this range owner is not specified as numeric UID
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* we are looking for. It may be specified as another
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* UID or as a literal username.
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*
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* If specified as another UID, the call to getpwnam()
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* will return NULL.
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*
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* If specified as literal username, we will get its
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* UID and compare that to UID we are looking for.
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*/
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const struct passwd *range_owner_pwd;
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range_owner_pwd = getpwnam(range->owner);
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if (NULL == range_owner_pwd) {
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continue;
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}
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if (owner_uid == range_owner_pwd->pw_uid) {
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return range;
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}
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}
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